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Chapter 10 : Gravitation
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The discussion is free for all,appearing in XI/Dip.Engg. Entrance -2018
Office:Silver Plaza, Opposite Kabir Colony , Anoop Shaher Road, Jamalpur Aligarh-202002, U.P-India
Chapter 10 : Gravitation
# Students are welcome to discuss online, the above mention MCQs.
The discussion is free for all,appearing in XI/Dip.Engg. Entrance -2018
Office:Silver Plaza, Opposite Kabir Colony , Anoop Shaher Road, Jamalpur Aligarh-202002, U.P-India
Contact Number: +91-9045756384,9548040225.
e-mail id : qacademyaligarh@gmail.com
Mohd Qasim .Gravitation sheet
ReplyDeleteQues 21 .The Gravitation for of attraction between two masses ,.,.,..................gravitational force of attraction between them
F= α = G.m1.m2/r^2 -------------------1
Deleter’ = (100-60)% of r = 0.4r
F’ = G.m1.m2/(0.4r)^2 = (1/0.4)^2.G.m1.m2/r^2
F’ = 6.25. G.m1.m2/r^2 = 6.25α (from 1)
Mohd Qasim Gravitation Sheet
ReplyDeleteQues 36 .An object of mass........
....Neglect the air resistance.
36. Ans: (b)
Deleteu = 0, m=m, t=t
h = ut-1/2 at^2
h = 0 - 1/( 2) 10 x t^2
H = -5t^2
Height of the tower = 5t^2
Mohd Qasim Gravitation Sheet.
ReplyDeleteQues 50. Calculate the .........mass is 20 kg
Weight = mg = 20x 9.8 = 196N
DeleteMohd Qasim Gravitation Sheet.
ReplyDeleteQues 51 . Calculate the,........mass is 20 kg
Sol. 51, Ans (b)
DeleteGravity on moon = one-sixth of gravity n earth = 10/6 m/s2
Weight on moon = mass x gravity at moon
= 20 x 10/6 = 33.33N
Mohd Qasim Gravitation Sheet.
ReplyDeleteQues 54 .When a person........on the ground.
Ans (a)
Deletethrust is the weight of the person and it will not change if he standing or lay down.
so, the thrust will be the same in both cases
Mohd Qasim Gravitation Sheet.
ReplyDeleteQues 62 .In Q61 what ..............table leg.
62. Ans: (d)
DeleteLoad on the table = 600N
Load on one leg = 600/4 = 150N
Area of each leg = 25cm2
Pressure increase on each leg = 150/25 = 6N/cm2 = 6000N/m2
Mohd Qasim Gravitation Sheet.
ReplyDeleteQues 64 . Three identical bricks .......
..........bricks will be
64. Ans (a)
DeleteThrust = Weight =mg = 30 x 9.8 =29.4
Mohd Qasim Gravitation Sheet.
ReplyDeleteQues 68 .The foundation of the buildings.
Pressure on the ground = weight of the building/ Area of footing of foundation.
DeleteThe load of the building comes on the columns and then to the foundation and finally to the ground.
Increasing the area of footing decreases the pressure on the ground.
Therefore, foundations decrease the pressure on the ground due to the weight of the building
Ans is (C )
Sir Q-31 ka ans d ho ga shayad lekin answersheet me c diya he
ReplyDeleteyes ...answer is d
ReplyDelete